The statment $ \sim \left( {p \leftrightarrow \sim q} \right)$ is
Equivalent to $p \leftrightarrow q$
'Equivalent to $ \sim p \leftrightarrow q$
A tautalogy
A fallacy
The statement $(\sim( p \Leftrightarrow \sim q )) \wedge q$ is :
Negation of the Boolean expression $p \Leftrightarrow( q \Rightarrow p )$ is.
Which of the following is true
If the truth value of the statement $(P \wedge(\sim R)) \rightarrow((\sim R) \wedge Q)$ is $F$, then the truth value of which of the following is $F$ ?
Consider the following two statements :
$P :$ lf $7$ is an odd number, then $7$ is divisible by $2.$
$Q :$ If $7$ is a prime number, then $7$ is an odd number.
lf $V_1$ is the truth value of the contrapositive of $P$ and $V_2$ is the truth value of contrapositive of $Q,$ then the ordered pair $(V_1, V_2)$ equals